Difference between revisions of "Binary systems"
Line 57: | Line 57: | ||
<div id=""></div> | <div id=""></div> | ||
<div style="border: 1px solid #AAA; padding:5px;"> | <div style="border: 1px solid #AAA; padding:5px;"> | ||
− | === Problem | + | === Problem 2: Gravitational luminosity=== |
Calculate the gravitational luminosity for the binary system with equal masses of the previous problem. | Calculate the gravitational luminosity for the binary system with equal masses of the previous problem. | ||
<br/> | <br/> | ||
Line 73: | Line 73: | ||
<div id=""></div> | <div id=""></div> | ||
<div style="border: 1px solid #AAA; padding:5px;"> | <div style="border: 1px solid #AAA; padding:5px;"> | ||
− | === Problem | + | === Problem 3: Asymmetric binary system=== |
Calculate the gravitational luminosity for a binary system with components of arbitrary masses $M_1$ and $M_2$. | Calculate the gravitational luminosity for a binary system with components of arbitrary masses $M_1$ and $M_2$. | ||
<br/> | <br/> | ||
Line 97: | Line 97: | ||
<div id=""></div> | <div id=""></div> | ||
<div style="border: 1px solid #AAA; padding:5px;"> | <div style="border: 1px solid #AAA; padding:5px;"> | ||
− | === Problem | + | === Problem 4: Binary system evolution=== |
Find the rate of the two components of a binary with masses $M_1$ and $M_2$ approaching due to emission of gravitational waves. Obtain the distance between them $R$ as a function of time. | Find the rate of the two components of a binary with masses $M_1$ and $M_2$ approaching due to emission of gravitational waves. Obtain the distance between them $R$ as a function of time. | ||
<br/> | <br/> | ||
Line 124: | Line 124: | ||
<div id=""></div> | <div id=""></div> | ||
<div style="border: 1px solid #AAA; padding:5px;"> | <div style="border: 1px solid #AAA; padding:5px;"> | ||
− | === Problem | + | === Problem 5: Binary system lifetime=== |
Calculate the lifetime of a binary system of mass $M$ and orbital radius $R$ due to emission of gravitational waves alone. Make estimates for the Hulse-Taylor binary pulsar PSR1913+16 with the following characteristics: $M\approx 2.8 M_\odot$, $R\approx 4.5 R_\odot$, $R_\odot \approx 7\times 10^8$m. | Calculate the lifetime of a binary system of mass $M$ and orbital radius $R$ due to emission of gravitational waves alone. Make estimates for the Hulse-Taylor binary pulsar PSR1913+16 with the following characteristics: $M\approx 2.8 M_\odot$, $R\approx 4.5 R_\odot$, $R_\odot \approx 7\times 10^8$m. | ||
<div class="NavFrame collapsed"> | <div class="NavFrame collapsed"> | ||
Line 141: | Line 141: | ||
<div id=""></div> | <div id=""></div> | ||
<div style="border: 1px solid #AAA; padding:5px;"> | <div style="border: 1px solid #AAA; padding:5px;"> | ||
− | === Problem | + | === Problem 6: Mass through GW frequency=== |
Show that the mass of a binary can be determined through the frequency of gravitational waves it generates. | Show that the mass of a binary can be determined through the frequency of gravitational waves it generates. | ||
<br/> | <br/> |
Revision as of 02:47, 8 January 2013
Contents
Problem 1: Symmetric binary system
Find the strain tensor $\bar{h}_{\alpha\beta}$ of the metric perturbation far from a binary system with components of equal masses $M$. The radius of the orbit is $R$, orbital frequency $\omega$.
Hint: Calculating the quadrupole moment of the system gives
\[\bar{h}^{\alpha\beta}
=-\frac{8\omega^2 MR^{2}}{r}
\left( \begin{matrix}
\cos \left[ 2\omega (t-r) \right]
& \sin \left[ 2\omega (t-r) \right] & 0 \\
\sin \left[ 2\omega (t-r) \right]
& -\cos \left[ 2\omega (t-r) \right] & 0 \\
0 & 0 & 0 \\
\end{matrix} \right)\]
Let the orbit lie in the $xy$-plane. Then the masses have trajectories \[\left( R\cos \omega t,\ R\sin \omega t,0 \right), \quad \left( -R\cos \omega t,\ -R\sin \omega t,0 \right)\] From the definition of the second mass moment \[I^{\alpha\beta}(t)=\int d^{3} x\; \rho (t,\mathbf{x})x^{\alpha}x^{\beta},\] ($\rho$ is the rest-mass density) we find for binary system \[I^{\alpha\beta}=MR^{2} \left( \begin{matrix} 1+\cos 2\omega t & \sin 2\omega t & 0 \\ \sin 2\omega t & 1-\cos 2\omega t & 0 \\ 0 & 0 & 0 \\ \end{matrix} \right).\] As we have seen above in the long-wavelength approximation $\lambda \gg R$ and the distant-source approximation $r\gg R$ the strain tensor is \[ \bar{h}^{\alpha\beta}(t,\mathbf{x}) =\frac{2}{r}\ddot{I}^{\alpha\beta}(t-r)\] Therefore, \[\bar{h}^{\alpha\beta} =-\frac{8\omega^2 MR^{2}}{r} \left( \begin{matrix} \cos \left[ 2\omega (t-r) \right] & \sin \left[ 2\omega (t-r) \right] & 0 \\ \sin \left[ 2\omega (t-r) \right] & -\cos \left[ 2\omega (t-r) \right] & 0 \\ 0 & 0 & 0 \\ \end{matrix} \right)\] Note that this representation of $\bar{h}^{\alpha\beta}$ is already in transverse traceless gauge for propagation in the $z$ direction. Also, the frequency of the emitted radiation is twice the orbital frequency by the symmetry of the problem.
Problem 2: Gravitational luminosity
Calculate the gravitational luminosity for the binary system with equal masses of the previous problem.
Hint: Calculating the quadrupole tensor's square and averaging gives
\[L_{GW}=\frac{128}{5}M^{2}R^{4}\omega^{6}.\]
The components of $Q^{\mu\nu}$ were calculated in the previous problem, so the quadrupole formula can be immediately applied to find the luminosity. The trace $Q_{\alpha}^{\alpha}=2MR^{2}$ is independent of time, so the time derivates of $I^{\alpha\beta}$ and $Q^{\alpha\beta}$ coincide. Averaging over the orbital period provides an additional factor of $1/2$ . The result for ${{L}_{GW}}$ is then \[L_{GW}=\frac{128}{5}M^{2}R^{4}\omega^{6}.\]
Problem 3: Asymmetric binary system
Calculate the gravitational luminosity for a binary system with components of arbitrary masses $M_1$ and $M_2$.
Hint: If $R$ is the distance between the components, then
\[L_{GW}=\frac{32}{5}\frac{G^4}{c^5}
\frac{M_1^2 M_2^2 (M_1 +M_2)}{R^5}.\]
Let $R$ be the distance between the components. Then the quadrupole formula gives \[L_{GW}=\frac{32G}{5c^5} \Big(\frac{M_{1}M_{2}}{M_{1}+M_{2}}\Big)^{2} R^{4}\omega^6.\] Frequency $\omega$ is related to $R$ through \[\omega^{2}R^{3}=G(M_{1}+M_{2}),\] so for the gravitational luminosity we finally obtain \[L_{GW}=\frac{32}{5}\frac{G^{4}}{c^5} \frac{M_{1}^{2}M_{2}^{2}(M_{1}+M_{2})}{R^5}.\]
Problem 4: Binary system evolution
Find the rate of the two components of a binary with masses $M_1$ and $M_2$ approaching due to emission of gravitational waves. Obtain the distance between them $R$ as a function of time.
Hint: Equating $dE(R)/dt$ to losses due to gravitational radiation, we obtain differential equation for $R(t)$. Integration yields
\[ R(t)=4\;\Big[
\frac{G^{3}M_{1}M_{2}(M_1 +M_2)}{5 c^5}
(t_{coal}-t)\Big]^{1/4}.\]
From the virial theorem $2\left\langle T \right\rangle =-\left\langle U \right\rangle$, the energy of the system is \[E=-G\frac{M_1 M_2}{2R},\] so \[\dot{R}=\frac{2R^{2}}{GM_{1}M_{2}}\frac{dE}{dt}.\] Then from $dE/dt=-L_{GW}$ and using the expression for the gravitational luminosity, we obtain \[\dot{R}=-\frac{64G^{3}}{5c^{2}} \frac{M_{1}M_{2}(M_{1}+M_{2})}{R^3}.\] Integrating from present time $t$ to the future time of coalescence ${{t}_{coal}}$, we have $R(t)$: \[ R(t)=2\;\Big[\frac{16}{5} \frac{G^{3}M_{1}M_{2}(M_1 +M_2)}{c^5} (t_{coal}-t)\Big]^{1/4}.\]
Problem 5: Binary system lifetime
Calculate the lifetime of a binary system of mass $M$ and orbital radius $R$ due to emission of gravitational waves alone. Make estimates for the Hulse-Taylor binary pulsar PSR1913+16 with the following characteristics: $M\approx 2.8 M_\odot$, $R\approx 4.5 R_\odot$, $R_\odot \approx 7\times 10^8$m.
For a binary with $M_1 =M_2 =M/2$ a rough estimate would be \[t_{chirp}\sim\frac{MV^{2}}{L_{GW}} =\frac{5M}{2}\Big(\frac{R}{M}\Big)^{4}.\] More accurate evaluation would use the time evolution of $R(t)$: for $M_1 =M_2 =M/2$ we get \[t_{chirp}=\frac{5}{16}\frac{c^5 R^4}{G^3 M^3}.\] This is of the order of $45\times 10^9$ years.
Problem 6: Mass through GW frequency
Show that the mass of a binary can be determined through the frequency of gravitational waves it generates.
Hint: It is possible thanks to the relation
\[f_{GW}=(1.9Hz)\Big(\frac{1.4M_{\odot}}{M}\Big)^{5/8}
\Big(\frac{days}{t_{coal}-t}\Big)^{3/8}.\]
From the previous problem for gravitational wave frequency for a binary with components of equal masses we get \begin{align*} f_{GW}&=\frac{\omega }{\pi } =\frac{1}{\pi }\Big(\frac{GM}{4R^3}\Big)^{1/2} =\frac{2^{1/8}5^{3/8}}{8\pi} \Big(\frac{c^3}{GM}\Big)^{5/8}(t_{coal}-t)^{-3/8}=\\ &=(1.9Hz)\Big(\frac{1.4M_{\odot}}{M}\Big)^{5/8} \Big(\frac{days}{\tau}\Big)^{3/8}, \quad \tau \equiv t_{coal}-t. \end{align*} Hence the mass of the compact binary system can be derived from the frequency evolution.