Difference between revisions of "Geometric warm-up"
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<p style="text-align: left;">In a flat space we have | <p style="text-align: left;">In a flat space we have | ||
| − | \[ | + | \[\alpha = \arccos \left( {1 - \frac{A^2}{2B^2}} \right),\] |
| − | \alpha = \arccos \left( {1 - \frac | + | |
| − | \] | + | |
while in a space of constant negative curvature with radius of curvature $R$ | while in a space of constant negative curvature with radius of curvature $R$ | ||
| − | \[ | + | \[\alpha = \arccos \left( {1 - \frac{\operatorname{ch} \left( {A/R} \right) - 1}{\operatorname{sh} ^2 (B/R)} \right).\] |
| − | \alpha = \arccos \left( {1 - \frac | + | |
| − | + | ||
| − | \] | + | |
When $R \to \infty $ this case turns into the flat one. The expression for constant positive curvate could be obtained by replacement $R \to iR$.</p> | When $R \to \infty $ this case turns into the flat one. The expression for constant positive curvate could be obtained by replacement $R \to iR$.</p> | ||
</div> | </div> | ||
</div></div> | </div></div> | ||
Revision as of 14:39, 20 August 2012
Problem 1
What is maximum sum of angles in a triangle on a sphere?
$540^\circ$.
Problem 1
- Consider the sphere of radius $R$. A circle is drawn on the sphere which has radius $r$ as measured along the sphere. Find the circumference of the circle as a function of $r$.
$\displaystyle L = 2\pi R\sin {r \over R}$.
Problem 1
Suppose that galaxies are distributed evenly on a two-dimensional sphere of radius $R$ with number density $n$ per unit area. Determine the total number $N$ of galaxies inside a radius $r$. Do you see more or fewer galaxies out to the same radius, compared to the flat case?
$N = 2\pi nR^2 \left( {1 - \cos {r \over R}} \right) \approx n\pi R^2 \left( {1 - {{r^2 } \over {12R^2 }}} \right) < n\pi R^2 $.
Problem 1
An object of size $A$ is situated at distance $B$. Determine the angle at which the object is viewed in flat space and in spaces of constant (positive and negative) curvature.
In a flat space we have \[\alpha = \arccos \left( {1 - \frac{A^2}{2B^2}} \right),\] while in a space of constant negative curvature with radius of curvature $R$ \[\alpha = \arccos \left( {1 - \frac{\operatorname{ch} \left( {A/R} \right) - 1}{\operatorname{sh} ^2 (B/R)} \right).\] When $R \to \infty $ this case turns into the flat one. The expression for constant positive curvate could be obtained by replacement $R \to iR$.
