Difference between revisions of "Wave equation"

From Universe in Problems
Jump to: navigation, search
(Problem 3: Wave equation from action)
Line 2: Line 2:
  
  
 +
 +
__TOC__
  
  

Revision as of 03:08, 8 January 2013




Problem 1: Lorenz (Hilbert, harmonic) gauge

The Lorenz\footnote{By analogy with electromagnetism; note the spelling: Lorenz, not Lorentz.} gauge conditions are \begin{equation} \label{LorenzGauge} \partial_{\mu}\bar{h}^{\mu\nu}=0. \end{equation} Write down the Einstein's equations in the Lorenz gauge.

Hint: They are reduced to the wave equation \begin{equation} \label{WaveEq} \square \bar{h}_{\mu\nu}=\frac{16\pi G}{c^4}T_{\mu\nu}. \end{equation}



Problem 2: Lorenz frame

Lorenz frame is the coordinate frame in which the Lorenz gauge conditions (\ref{LorenzGauge}) are satisfied.
1) find the coordinate transformation $x^\mu \to {x'}^{\mu}=x^\mu +\xi^\mu$ from a given frame to the Lorenz frame;
2) is the Lorenz frame unique? what is the remaining freedom for the choice of $\xi^\mu$?

Hint:

1) The equation for $\xi^\mu$ is $\square \xi^\mu =\partial_{\nu}{\bar{h}^{\nu}}_{\mu}$;
2) no, any $\xi^\mu$ satisfying $\square \xi^{\mu}=0$ preserves the Lorenz gauge.



Problem 3: Wave equation from action

Obtain the Einstein's equation in the Lorenz gauge in the first order by $h$ directly from the action



Problem 4: Vacuum equations in the transverse gauge

Simplify the vacuum Einstein's equations in the transverse gauge (without the Lorenz gauge conditions), assuming vanishing boundary conditions.

Hint:

$\Phi=\Psi=0,\quad w^\alpha =0,\quad \square s_{\alpha\beta}=0$


The only difference of the wave equation for gravitational perturbations from the one for the electromagnetic field is in its tensorial nature. The Green's function for the wave equation is known (see e.g. here or here), and the retarded solution, which is usually thought of as the one physically relevant, is \begin{equation} \bar{h}_{\mu\nu}(t,\mathbf{x})=\frac{1}{4\pi}\int \frac{d^{3}x'}{|\mathbf{x}-\mathbf{x'}|}\cdot \frac{16\pi G}{c^4}T_{\mu\nu} \Big(t-\frac{|\mathbf{x}-\mathbf{x'}|}{c}, \mathbf{x'}\Big). \end{equation}