The most important prediction of the supersymmetry is the fact that every particle has a super-partner with the spin which differs on $1/2$. Without special caution, the appearance of the super-partners may lead to violation of baryon and lepton quantum numbers on an inadmissible level. For example, the proton decay $p \to \pi ^0+ e^+ $ can be realized with help of the $s$-quark (it is the super-partner for the usual one). An elegant way to prohibit the decay is to impose the $R$-parity conservation condition $R_p = ( - 1)^{3(B - L) + 2S},$ where
$B,L,S$ are baryon number, leptonnumber and spin respectively
(recall that baryons are hadrons with semi-integral spin). All the Standard Model particles have $R_p = 1,$ and all the super-partners have $R_p = - 1.$ Conservation of the $R$-parity implies that $\prod {R_p
= 1}$ holds in every vertex. The proton decay can be forbidden without the notion of the $R$-parity conservation. For example it can be done by forbidding of the $B$ or $L$ violation, but not both of them. However it leads to even more difficulties. Direct consequences of the $R$-parity conservation are the following:
1) The lightest supersymmetric particle (LSP) cannot decay on the Standard Model particles and therefore it is stable.
2) The supersymmetric particles are created in pairs only.
3) Supersymmetric particles can decay only on odd number of supersymmetric particles.