The energy flux the wave carries is quadratic in amplitude, so from energy conservation
\[h^{2}R^{2}=const,\]
where $h$ is the amplitude, $R$ distance to source. At If $R_*$ is the characteristic size of the supernova, and $h_0$ the characteristic amplitude at such distances from the source, then at Earth the amplitude will be
\[h=h_{0}\frac{R_*}{R}.\]
If the explosion leads to creation of a neutron star or a black hole, $R_*$ can be estimated by the gravitational radius
\[R_{*}\sim \frac{2GM}{c^2}
\approx 3km\frac{M}{M_\odot}.\]
The amplitude $h_0$ is determined by the efficiency $\alpha $ of the conversion of the full energy into that of gravitational waves
\[h_{0}=\alpha^{1/2},\]
so
\[h\sim \alpha^{1/2}
\frac{M}{M_\odot}\frac{3km}{R(km)}.\]
If the explosion happens at the center of our galaxy $R\sim 10kpc\approx 3\times 10^{7}km$, then assuming $M/M_{*}\approx 3$, we will obtain
\[h\sim \alpha^{1/2}\times 10^{-17}.\]
For $\alpha \sim 10^{-2}\div 10^{-6}$ the value is reasonably encouraging $h\sim {10}^{-18}\div {10}^{-21}$. But reality might be quite different.